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php: prevent error duplication

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Turn off `display_errors` and empty the `error_log` option so that
errors are guaranteed to be output to stdout

See #186 for discussion.
This commit is contained in:
Martin Grenfell 2012-03-02 09:25:40 +00:00
parent de9f81b7e0
commit 1f91303cdc
1 changed files with 1 additions and 1 deletions
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syntax_checkers/php.vim
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@ -38,7 +38,7 @@ function! SyntaxCheckers_php_GetLocList()
let errors = []
let makeprg = "php -l -d error_reporting=E_PARSE -d display_errors=1 ".shellescape(expand('%'))
let makeprg = "php -l -d error_reporting=E_PARSE -d display_errors=0 -d error_log='' ".shellescape(expand('%'))
let errorformat='%-GNo syntax errors detected in%.%#,PHP Parse error: %#syntax %trror\, %m in %f on line %l,PHP Fatal %trror: %m in %f on line %l,%-GErrors parsing %.%#,%-G\s%#,Parse error: %#syntax %trror\, %m in %f on line %l,Fatal %trror: %m in %f on line %l'
let errors = SyntasticMake({ 'makeprg': makeprg, 'errorformat': errorformat })